y^2+36y+247=0

Solution for y^2+36y+247=0 equation:

y^2+36y+247=0

a = 1; b = 36; c = +247;
Δ = b2-4ac
Δ = 362-4·1·247
Δ = 308
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{308}=\sqrt{4*77}=\sqrt{4}*\sqrt{77}=2\sqrt{77}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2\sqrt{77}}{2*1}=\frac{-36-2\sqrt{77}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2\sqrt{77}}{2*1}=\frac{-36+2\sqrt{77}}{2}
$